Question

given ((x - 7)^2 = 36), select the values of (x).
(x = 13)
(x = 1)
(x = -29)
(x = 42)
done

Explanation:

Step1: Take square root of both sides

$\sqrt{(x-7)^2} = \sqrt{36}$
$x-7 = \pm 6$

Step2: Solve for positive case

$x-7 = 6$
$x = 6 + 7$
$x = 13$

Step3: Solve for negative case

$x-7 = -6$
$x = -6 + 7$
$x = 1$

Answer:

A. $x = 13$, B. $x = 1$