Question

given (4c + 5
eq 0) and (c) is a real number, what is the multiplicative inverse of (4c + 5)? (\frac{1}{4c + 5}) (\frac{1}{4c}+5) (1) (0)

Explanation:

Step1: Recall multiplicative inverse definition

For a non-zero real number $x$, its multiplicative inverse $y$ satisfies $x \cdot y = 1$.

Step2: Solve for inverse of $4c+5$

Let $x=4c+5$, solve $x \cdot y=1$ for $y$:
$y = \frac{1}{x} = \frac{1}{4c+5}$

Answer:

$\frac{1}{4c+5}$