Question

given is the data for temperature vs ice cream sales for a shop in july of 2022. a linear regression was performed and the line of best fit is $y = 7.09774x - 402.554$. use the regression to extrapolate the approximate ice cream sales when the temperature is 150 degrees f. \bigcirc 150 is not on the graph so extrapolation is not possible. \bigcirc 150 degrees f is not a reasonable domain value for the situation, so extrapolation will not be accurate. \bigcirc 78 degrees f \bigcirc 862

Explanation:

Step1: Substitute temperature value

Substitute $x=150$ into the regression equation $y = 7.09774x - 402.554$.
$y = 7.09774\times150 - 402.554$

Step2: Calculate the product

Compute $7.09774\times150$.
$7.09774\times150 = 1064.661$

Step3: Compute final sales value

Subtract 402.554 from the product.
$y = 1064.661 - 402.554 = 662.107 \approx 662$

Answer:

$662$ (corresponding to the option: $662$)