Question

given the equation $x^{2}-16x + 20 = 0$ to make the left side a perfect square trinomial, what number must be added to both sides of the equation? use the keypad to enter the missing values or expressions in the boxes. additional symbols can be found using the drop - down arrows at the top of the keypad. $x^{2}-16x+square=-20+square$

Explanation:

Step1: Isolate constant term

$x^2 - 16x = -20$

Step2: Find perfect square constant

Take half of $-16$: $\frac{-16}{2} = -8$, square it: $(-8)^2 = 64$

Step3: Add to both sides

$x^2 - 16x + 64 = -20 + 64$

Answer:

The number to add to both sides is 64, so the filled equation is $x^2 - 16x + 64 = -20 + 64$