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if given the equation y = 3(x + 5)^2 - 4, what is the vertex of the par…

Question

if given the equation y = 3(x + 5)^2 - 4, what is the vertex of the parabola? (-5, -4) (5, -4)

Explanation:

Step1: Recall vertex - form of parabola

The vertex - form of a parabola is $y=a(x - h)^2+k$, where $(h,k)$ is the vertex of the parabola.

Step2: Rewrite the given equation in vertex - form

The given equation is $y = 3(x + 5)^2-4$, which can be written as $y=3(x-(- 5))^2+(-4)$.

Answer:

$(-5,-4)$