Question

given that $g(x)=x^{2}-3x-9$, find $(g \circ g)(-3)$.

$(g \circ g)(-3)=\square$ (simplify your answer.)

Explanation:

Step1: Calculate $g(-3)$

Substitute $x=-3$ into $g(x)$:
$g(-3) = (-3)^2 - 3(-3) - 9$
$g(-3) = 9 + 9 - 9 = 9$

Step2: Calculate $g(g(-3))=g(9)$

Substitute $x=9$ into $g(x)$:
$g(9) = 9^2 - 3(9) - 9$
$g(9) = 81 - 27 - 9 = 45$

Answer:

45