Question

given rhombus lmno below, op = 29. if pm = -x + 6, solve for x.

Explanation:

Step1: Recall rhombus diagonals property

In a rhombus, the diagonals bisect each other. So \( OP = PM \).

Step2: Set up the equation

Given \( OP = 29 \) and \( PM=-x + 6 \), we have the equation \( -x+6 = 29 \).

Step3: Solve for \( x \)

Subtract 6 from both sides: \( -x=29 - 6 \), so \( -x = 23 \). Multiply both sides by -1: \( x=- 23 \).

Answer:

\( x=-23 \)