Question

given right triangle jkl, what is the value of cos(l)? - 5/13 - 5/12 - 12/13 - 12/5

Explanation:

Step1: Identify right triangle sides

Right angle at K: JK=12, KL=5, hypotenuse JL.

Step2: Calculate hypotenuse JL

By Pythagoras: $JL=\sqrt{JK^2+KL^2}=\sqrt{12^2+5^2}=\sqrt{169}=13$.

Step3: Find cos(L)

$\cos(L)=\frac{\text{adjacent to } L}{\text{hypotenuse}}=\frac{KL}{JL}=\frac{5}{13}$.

Answer:

A. $\frac{5}{13}$