Question

given right triangle pqr, which represents the value of sin(p)?
o $\frac{rp}{rq}$
o $\frac{rp}{pq}$
o $\frac{rq}{pq}$
o $\frac{rq}{pr}$

Explanation:

Step1: Recall sine - definition

In a right - triangle, for an acute angle $\theta$, $\sin(\theta)=\frac{\text{opposite}}{\text{hypotenuse}}$.

Step2: Identify opposite and hypotenuse for angle $P$

For angle $P$ in right - triangle $PQR$, the side opposite to angle $P$ is $RQ$ and the hypotenuse is $PQ$.

Step3: Calculate $\sin(P)$

So, $\sin(P)=\frac{RQ}{PQ}$.

Answer:

$\frac{RQ}{PQ}$ (the third option)