Question

6.gm.25 dok 2

1. mr. allen gets 24 miles to the gallon (mpg) in his jeep. on a trip he uses 12 gallons of gas and travels at an average rate of speed of 50 miles per hour. which formula below will find the distance mr. allen traveled?

① $d = (24)(mph)g$
② $d = mpg$
③ $d = (mpg)g$
④ $d = (mpg)(mph)$
6.af.21 dok 2

1. the two expressions that are equivalent to $4(x - 10)$. select all that apply.

① $4x - 5$
② $4x - 40$
③ $(2x - 2) + (2x - 8)$
④ $3(x - 5) + (x - 5)$
⑤ $2( x - 10) + 2(x - 10)$
6.nso.7 dok 2

Explanation:

Question 5

Step1: Recall distance-mpg-gallon relation

Distance equals miles per gallon multiplied by gallons used.

Step2: Match to variable notation

Here, $mpg$ = miles per gallon, $g$ = gallons, so $d=(mpg)g$.

Step1: Expand the original expression

Use distributive property: $4(x-10)=4x-40$.

Step2: Check option a

$4x-5
eq 4x-40$, not equivalent.

Step3: Check option b

$4x-40$ matches the expanded form, equivalent.

Step4: Check option c

Simplify: $(2x-2)+(2x-8)=4x-10
eq 4x-40$, not equivalent.

Step5: Check option d

Simplify: $3(x-5)+(x-5)=4(x-5)=4x-20
eq 4x-40$, not equivalent.

Step6: Check option e

Simplify: $2(x-10)+2(x-10)=4(x-10)$, matches original, equivalent.

Answer:

c. $d = (mpg)g$

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Question 6