Question

graph the image of s(0, -6) after a reflection over the x - axis.

Explanation:

Step1: Recall reflection rule

The rule for reflecting a point $(x,y)$ over the $x - axis$ is $(x,-y)$.

Step2: Apply rule to point S

For point $S(0, - 6)$, where $x = 0$ and $y=-6$, after reflection, the new $y$-coordinate is $-(-6)=6$ and $x$ remains $0$. So the image is $(0,6)$.

Answer:

The image of $S(0,-6)$ after reflection over the $x - axis$ is the point $(0,6)$. To graph it, locate the point on the $y$-axis at $y = 6$ (since $x = 0$).