Question

graph the image of s(-9, 0) after a reflection over the y - axis.

Explanation:

Step1: Recall reflection rule

When reflecting a point $(x,y)$ over the $y - axis$, the rule is $(-x,y)$.

Step2: Apply rule to point S

For point $S(-9,0)$, using the rule $(-x,y)$, we get $-(-9)=9$, so the new point is $(9,0)$.

Answer:

The image of $S(-9,0)$ after reflection over the $y - axis$ is $(9,0)$. To graph it, locate the point $(9,0)$ on the $x - axis$ (9 units to the right of the origin).