Question

graph the image of △stu after a reflection over the x - axis.

Explanation:

Step1: Recall reflection rule

The rule for reflecting a point $(x,y)$ over the $x -$axis is $(x,-y)$.

Step2: Identify vertices of $\triangle STU$

Let's assume the coordinates of $S$ are $(x_1,y_1)$, of $T$ are $(x_2,y_2)$ and of $U$ are $(x_3,y_3)$. From the graph, if $S(- 3,-3)$, $T(6,-3)$ and $U(-3,-7)$.

Step3: Apply reflection rule to each vertex

For point $S(-3,-3)$, after reflection over the $x -$axis, the new point $S'$ has coordinates $(-3,3)$.
For point $T(6,-3)$, after reflection over the $x -$axis, the new point $T'$ has coordinates $(6,3)$.
For point $U(-3,-7)$, after reflection over the $x -$axis, the new point $U'$ has coordinates $(-3,7)$.

Step4: Graph the new triangle

Plot the points $S'(-3,3)$, $T'(6,3)$ and $U'(-3,7)$ and connect them to form the reflected triangle $\triangle S'T'U'$.

Answer:

Graph the points $(-3,3)$, $(6,3)$ and $(-3,7)$ and connect them to get the image of $\triangle STU$ after reflection over the $x -$axis.