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2 graph △lmn with l(3, -7), m(8, -4), n(1, -2), and its image after a c…

Question

2 graph △lmn with l(3, -7), m(8, -4), n(1, -2), and its image after a counterclockwise rotation of 270° about the origin. what are the coordinates of lmn? a) l(7, 3), m(4, 8), n(2, 1) forced b) l(-7, -3), m(-4, -8), n(-2, -1) tickled pink c) l(7, -3), m(8, -4), n(2, -1) embarrassed d) l(-3, 7), m(8, 4), n(-1, 2) scared e) l(-7, -3), m(-8, -4), n(2, -1) inspired

Explanation:

Step1: Recall rotation rule

A $270^{\circ}$ counter - clockwise rotation about the origin has the rule $(x,y)\to(y, - x)$.

Step2: Apply rule to point L

For $L(3,-7)$, using the rule $(x = 3,y=-7)\to(y,-x)=(-7,-3)$.

Step3: Apply rule to point M

For $M(8,-4)$, $(x = 8,y = - 4)\to(y,-x)=(-4,-8)$.

Step4: Apply rule to point N

For $N(1,-2)$, $(x = 1,y=-2)\to(y,-x)=(-2,-1)$.
The correct answer is A as it follows the $(x,y)\to(y,-x)$ rule for each point.

Answer:

A. $L'(7,3), M'(4,8), N'(2,1)$