Question

the graph shows the temperature in a kiln while firing a piece of pottery. over which time interval did the temperature in the kiln have the greatest rate of change?

Explanation:

Step1: Calculate rate of change formula

Rate of change = $\frac{\Delta y}{\Delta x}=\frac{y_2 - y_1}{x_2 - x_1}$

Step2: Calculate rates for intervals

For $0 - 1.4$ hours: $\frac{1125 - 245}{1.4-0}=\frac{880}{1.4}\approx628.57$
For $1.4 - 2.5$ hours: $\frac{1300 - 1125}{2.5 - 1.4}=\frac{175}{1.1}\approx159.09$
For $2.5 - 4.6$ hours: $\frac{1675 - 1300}{4.6 - 2.5}=\frac{375}{2.1}\approx178.57$
For $4.6 - 8.3$ hours: $\frac{1925 - 1675}{8.3 - 4.6}=\frac{250}{3.7}\approx67.57$

Answer:

$0 - 1.4$ hours