Question

graphing practice 2
the data table below represents the distance traveled by a car. graph the distance and time data on the graph below. dont forget to label the axes (hint: time always goes on the x - axis). draw straight lines connecting your data points.

time (s)	distance (m)
1	20
2	40
3	60
4	60
5	60
6	70
7	80
8	90

1. using the graph above, calculate the speed of the car between 0 and 3 seconds. show your work and include units.

using the graph above, calculate the speed of the car between 3 and 5 seconds. show your work and include units.
using the graph above, calculate the speed of the car between 5 and 8 seconds. show your work and include units.
describe what is happening to the car between 3 and 5 seconds.

Explanation:

Sub - Question 1: Calculate speed between 0 and 3 seconds

Step 1: Recall the formula for speed

Speed is calculated as the ratio of distance traveled to the time taken, i.e., \(v=\frac{d}{t}\), where \(v\) is speed, \(d\) is distance, and \(t\) is time.

Step 2: Identify distance and time values

From the data table (or graph), at \(t = 0\) s, distance \(d_1=0\) m and at \(t = 3\) s, distance \(d_2 = 60\) m. The time interval \(\Delta t=t_2 - t_1=3 - 0 = 3\) s, and the distance traveled \(\Delta d=d_2 - d_1=60 - 0 = 60\) m.

Step 3: Calculate speed

Using the speed formula \(v=\frac{\Delta d}{\Delta t}\), substitute \(\Delta d = 60\) m and \(\Delta t=3\) s. So, \(v=\frac{60\space m}{3\space s}=20\space m/s\).

Step 1: Recall the speed formula

The formula for speed is \(v=\frac{d}{t}\).

Step 2: Identify distance and time values

At \(t = 3\) s, distance \(d_1 = 60\) m and at \(t = 5\) s, distance \(d_2=60\) m. The time interval \(\Delta t=t_2 - t_1=5 - 3 = 2\) s, and the distance traveled \(\Delta d=d_2 - d_1=60 - 60 = 0\) m.

Step 3: Calculate speed

Using the speed formula \(v=\frac{\Delta d}{\Delta t}\), substitute \(\Delta d = 0\) m and \(\Delta t = 2\) s. So, \(v=\frac{0\space m}{2\space s}=0\space m/s\).

Step 1: Recall the speed formula

The formula for speed is \(v=\frac{d}{t}\).

Step 2: Identify distance and time values

At \(t = 5\) s, distance \(d_1 = 60\) m and at \(t = 8\) s, distance \(d_2 = 90\) m. The time interval \(\Delta t=t_2 - t_1=8 - 5 = 3\) s, and the distance traveled \(\Delta d=d_2 - d_1=90 - 60 = 30\) m.

Step 3: Calculate speed

Using the speed formula \(v=\frac{\Delta d}{\Delta t}\), substitute \(\Delta d = 30\) m and \(\Delta t = 3\) s. So, \(v=\frac{30\space m}{3\space s}=10\space m/s\).

Answer:

The speed of the car between 0 and 3 seconds is \(20\space m/s\).

Sub - Question 2: Calculate speed between 3 and 5 seconds