Question

the half - life of a particular radioactive substance is 3 years. if you started with 60 grams of this substance, how much of it would remain after 6 years? remaining amount = 60(1 - 0.50)^ remaining amount = i(1 - r)^t enter the number that belongs in the green box.

Explanation:

Step1: Determine the number of half - lives

The half - life is 3 years and the time elapsed is 6 years. So the number of half - lives $n=\frac{6}{3}=2$.

Step2: Identify the formula variables

In the formula $Remaining\ Amount = I(1 - r)^t$, $I = 60$ (initial amount), $r = 0.5$ (rate of decay for half - life), and $t$ represents the number of half - lives. Here $t = 2$.

Answer:

2