Question

harue draws △efg on the coordinate plane as shown. then he reflects △efg across the x - axis to form △efg. what are the coordinates of the vertices of △efg? use the number pad to enter your answers in the boxes. the coordinates of vertex e are ( , ). the coordinates of vertex f are ( , ). the coordinates of vertex g are ( , ).

Explanation:

Step1: Recall reflection rule

When reflecting a point $(x,y)$ across the $x - axis$, the rule is $(x,y)\to(x, - y)$.

Step2: Find coordinates of $E'$

Assume $E=(3, - 2)$. Applying the rule, $E'=(3,-(-2))=(3,2)$.

Step3: Find coordinates of $F'$

Assume $F=(5,-4)$. Applying the rule, $F'=(5,-(-4))=(5,4)$.

Step4: Find coordinates of $G'$

Assume $G=(1,-4)$. Applying the rule, $G'=(1,-(-4))=(1,4)$.

Answer:

The coordinates of vertex $E'$ are $(3,2)$.
The coordinates of vertex $F'$ are $(5,4)$.
The coordinates of vertex $G'$ are $(1,4)$.