Question

henry can lift a 200 n load 20 m up a ladder in 40 s. ricardo can lift twice the load up one - half the distance in the same amount of time. which comparison between ricardo and henry is correct? ricardo exerted a greater force, did the same amount of work, and had the same power output as henry. ricardo exerted a greater force, did the same amount of work, and had a greater power output than henry. ricardo exerted a greater force, did less work, and had a greater power output than henry. ricardo exerted a smaller force, did more work, and had a lower power output than henry. ricardo exerted a smaller force, did more work, and had the same power output as henry.

Explanation:

Step1: Calculate Henry's force, distance and time

Henry's force $F_H = 200$ N, distance $d_H=20$ m, time $t_H = 40$ s.

Step2: Calculate Henry's work

Work formula is $W = F\times d$. So Henry's work $W_H=F_H\times d_H=200\times20 = 4000$ J.

Step3: Calculate Henry's power

Power formula is $P=\frac{W}{t}$. So Henry's power $P_H=\frac{W_H}{t_H}=\frac{4000}{40}=100$ W.

Step4: Calculate Ricardo's force, distance and time

Ricardo's force $F_R = 2\times200=400$ N, distance $d_R=\frac{20}{2}=10$ m, time $t_R = 40$ s.

Step5: Calculate Ricardo's work

Using work formula, Ricardo's work $W_R=F_R\times d_R=400\times10 = 4000$ J.

Step6: Calculate Ricardo's power

Using power formula, Ricardo's power $P_R=\frac{W_R}{t_R}=\frac{4000}{40}=100$ W.

Step7: Compare

Ricardo exerted a greater force ($400$ N > $200$ N), did the same amount of work ($W_R = W_H=4000$ J), and had the same power output ($P_R = P_H = 100$ W).

Answer:

Ricardo exerted a greater force, did the same amount of work, and had the same power output as Henry.