Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

at high temperature, so₂ and no₂ react according to the equation below.…

Question

at high temperature, so₂ and no₂ react according to the equation below. determine the equilibrium constant for this reaction by constructing an ice table, writing the equilibrium constant expression, and solving it. complete parts 1 - 2 before submitting your answer.

  1. so₂(g) + no₂(g) = so₃(g) + no(g)
  2. a 1.00 l reaction vessel was filled with 2.00 mol so₂ and 2.00 mol no₂. at equilibrium, there were 1.30 mol of no in the vessel. fill in the ice table with the appropriate value for each species.

Explanation:

Step1: Calculate initial concentrations

The volume of the vessel is $V = 1.00\ L$. Initial moles of $SO_2$ and $NO_2$ are $n_{SO_2}=n_{NO_2}=2.00\ mol$, and initial moles of $SO_3$ and $NO$ are $0$. Initial concentrations are calculated using $C=\frac{n}{V}$. So, $[SO_2]_{initial}=[NO_2]_{initial}=\frac{2.00\ mol}{1.00\ L}=2.00\ M$, and $[SO_3]_{initial} = [NO]_{initial}=0\ M$.

Step2: Define the change in concentrations

Let the change in concentration of $SO_2$ (and also $NO_2$ since the stoichiometric coefficient is 1 in the reaction $SO_2(g)+NO_2(g)
ightleftharpoons SO_3(g)+NO(g)$) be $x$. Then the change in concentration of $SO_3$ and $NO$ will also be $x$ due to the 1:1:1:1 stoichiometry of the reaction.

Step3: Calculate equilibrium concentrations

At equilibrium, $[SO_2]_{equilibrium}=2.00 - x$, $[NO_2]_{equilibrium}=2.00 - x$, $[SO_3]_{equilibrium}=x$, $[NO]_{equilibrium}=x$. We know that at equilibrium, moles of $NO_2$ are $2.00\ mol$ and moles of $NO$ are $1.30\ mol$. Since $V = 1.00\ L$, $[NO_2]_{equilibrium}=\frac{2.00\ mol}{1.00\ L}=2.00\ M$ and $[NO]_{equilibrium}=\frac{1.30\ mol}{1.00\ L}=1.30\ M$. So the change $x = 1.30\ M$. Then $[SO_2]_{equilibrium}=2.00 - 1.30=0.70\ M$, $[NO_2]_{equilibrium}=2.00 - 1.30 = 0.70\ M$, $[SO_3]_{equilibrium}=1.30\ M$, $[NO]_{equilibrium}=1.30\ M$.

SpeciesInitial (M)Change (M)Equilibrium (M)
$NO_2$$2.00$$- 1.30$$0.70$
$SO_3$$0$$1.30$$1.30$
$NO$$0$$1.30$$1.30$

Answer:

SpeciesInitial (M)Change (M)Equilibrium (M)
$NO_2$$2.00$$- 1.30$$0.70$
$SO_3$$0$$1.30$$1.30$
$NO$$0$$1.30$$1.30$