Question

higher order thinking the table shows the temperatures of the water in 14 different beakers. what is the average temperature, rounded to the nearest tenth of a degree?

Explanation:

Since the table with the temperature values is not provided, we'll assume the temperatures are \(t_1,t_2,\cdots,t_{14}\).

Step1: Recall the formula for the average

The formula for the average (arithmetic - mean) of a set of numbers \(x_1,x_2,\cdots,x_n\) is \(\bar{x}=\frac{\sum_{i = 1}^{n}x_i}{n}\). Here, \(n = 14\) and \(x_i=t_i\) for \(i=1,2,\cdots,14\). So the average temperature \(\bar{t}=\frac{t_1 + t_2+\cdots+t_{14}}{14}=\frac{\sum_{i = 1}^{14}t_i}{14}\).

Step2: Assume we have the values

Let's say the sum of the 14 temperatures \(\sum_{i = 1}^{14}t_i = S\). Then \(\bar{t}=\frac{S}{14}\).

Step3: Round the result

After calculating \(\frac{S}{14}\), we round the result to the nearest tenth.

Since we don't have the actual values of the temperatures, we can't give a numerical answer. But if we had the values, we would follow the above steps.

Answer:

We need the actual temperature values in the table to calculate the average temperature rounded to the nearest tenth.