Question

homework a.2.3
score: 16/17 answered: 16/17
question 17
find the area of a triangle with base 1\frac{2}{3} inches and height 11 inches?
write your answer as a proper fraction or mixed number in reduced form.
area = square inches
question help: read video post to forum

Explanation:

Step1: Convert mixed - number to improper fraction

$1\frac{2}{3}=\frac{1\times3 + 2}{3}=\frac{5}{3}$

Step2: Apply triangle area formula

The area formula of a triangle is $A=\frac{1}{2}\times b\times h$, where $b$ is the base and $h$ is the height. Substitute $b = \frac{5}{3}$ inches and $h = 11$ inches into the formula. So $A=\frac{1}{2}\times\frac{5}{3}\times11$.

Step3: Calculate the product

$A=\frac{1\times5\times11}{2\times3}=\frac{55}{6}$

Step4: Convert to mixed - number

$\frac{55}{6}=9\frac{1}{6}$

Answer:

$9\frac{1}{6}$