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4. how does the activation energy (ea) of the reverse reaction relate t…

Question

  1. how does the activation energy (ea) of the reverse reaction relate to the ea of the forward reaction and the enthalpy change (δh) for an endothermic reaction?

a. $e_{a(reverse)} = e_{a(forward)} - δh$
b. $e_{a(reverse)} = δh$
c. $e_{a(reverse)} = e_{a(forward)}$
d. $e_{a(reverse)} = -δh$
e. $e_{a(reverse)} = e_{a(forward)} + δh$

Explanation:

Response

To solve this, we analyze the relationship between activation energies (\(E_a\)) of forward and reverse reactions and enthalpy change (\(\Delta H\)) for an endothermic reaction.

Key Concepts:

For a reaction, the enthalpy change \(\Delta H\) is related to the activation energies of the forward (\(E_{a(\text{forward})}\)) and reverse (\(E_{a(\text{reverse})}\)) reactions by:
\[
\Delta H = E_{a(\text{forward})} - E_{a(\text{reverse})}
\]
For an endothermic reaction, \(\Delta H > 0\) (heat is absorbed, so products have higher energy than reactants).

Step 1: Rearrange the formula for \(E_{a(\text{reverse})}\)

Starting with \(\Delta H = E_{a(\text{forward})} - E_{a(\text{reverse})}\), rearrange to solve for \(E_{a(\text{reverse})}\):
\[
E_{a(\text{reverse})} = E_{a(\text{forward})} - \Delta H
\]

Step 2: Interpret for endothermic \(\Delta H\)

In an endothermic reaction, \(\Delta H\) is positive. From the rearranged formula:

  • \(E_{a(\text{forward})}\) is the energy needed to go from reactants to transition state.
  • \(E_{a(\text{reverse})}\) is the energy needed to go from products (higher energy, since endothermic) to transition state.

The formula \(E_{a(\text{reverse})} = E_{a(\text{forward})} - \Delta H\) matches option a.

Verify other options:
  • Option b: \(E_{a(\text{reverse})} = \Delta H\) is incorrect (no basis in the energy relationship).
  • Option c: \(E_{a(\text{reverse})} = E_{a(\text{forward})}\) would imply \(\Delta H = 0\), which is not endothermic.
  • Option d: \(E_{a(\text{reverse})} = -\Delta H\) would imply \(E_{a(\text{forward})} = 0\), which is impossible.
  • Option e: \(E_{a(\text{reverse})} = E_{a(\text{forward})} + \Delta H\) would make \(\Delta H\) negative (exothermic), contradicting endothermic.

Answer:

a. \( E_{\text{reverse}} = E_{\text{forward}} - \Delta H \)