Question

how many co₂ molecules are there in 2.45 ml co₂? (hint 1000 ml = 1 l and 1 mol of any gas = 22.4 l of that gas)
parts of the free response question that require calculations, clearly show the method used and the steps involved in arriving at your answers. you must show your wor
eceive credit for your answer. examples and equations may be included in your answers where appropriate.

Explanation:

Step1: Convert volume to liters

Given \( 2.45 \, \text{mL} \) of \( \text{CO}_2 \), convert to liters using \( 1000 \, \text{mL} = 1 \, \text{L} \).
\( \text{Volume (L)} = \frac{2.45 \, \text{mL}}{1000 \, \text{mL/L}} = 0.00245 \, \text{L} \)

Step2: Find moles of \( \text{CO}_2 \)

Using molar volume (\( 22.4 \, \text{L/mol} \)):
\( \text{Moles} = \frac{\text{Volume (L)}}{\text{Molar Volume (L/mol)}} = \frac{0.00245 \, \text{L}}{22.4 \, \text{L/mol}} \approx 1.09375 \times 10^{-4} \, \text{mol} \)

Step3: Calculate molecules using Avogadro's number (\( 6.022 \times 10^{23} \, \text{molecules/mol} \))

\( \text{Molecules} = \text{Moles} \times 6.022 \times 10^{23} \, \text{molecules/mol} \)
\( \text{Molecules} = 1.09375 \times 10^{-4} \, \text{mol} \times 6.022 \times 10^{23} \, \text{molecules/mol} \approx 6.586 \times 10^{19} \)

Answer:

Approximately \( 6.59 \times 10^{19} \) \( \text{CO}_2 \) molecules (or \( 6.586 \times 10^{19} \) for more precision).