Question

how many grams of silver(i)nitrite are needed to prepare 250 ml of a 0.125m solution? -use correct significant digits and no unit-

Explanation:

Step1: Convert volume to liters

$250\ \text{mL} = \frac{250}{1000} = 0.250\ \text{L}$

Step2: Calculate moles of solute

Moles = Molarity × Volume
$\text{Moles of AgNO}_2 = 0.125\ \text{mol/L} \times 0.250\ \text{L} = 0.03125\ \text{mol}$

Step3: Find molar mass of AgNO₂

Molar mass of Ag = 107.87 g/mol, N = 14.01 g/mol, O = 16.00 g/mol
$\text{Molar mass} = 107.87 + 14.01 + (2 \times 16.00) = 153.88\ \text{g/mol}$

Step4: Calculate mass of solute

Mass = Moles × Molar mass
$\text{Mass} = 0.03125\ \text{mol} \times 153.88\ \text{g/mol} = 4.80875$

Step5: Round to correct sig figs

Round to 3 significant digits

Answer:

4.81