Question

1
how many moles of aluminium are needed to react completely with 1.2 mol of feo? *
(0.5 points)

2al(s) + 3feo(s) → 3fe(s) + al₂o₃(s)

0.8 mol

2.4 mol

1.6 mol

1.2 mol

2
how many atoms of nitrogen are there in 0.50 mol of (nh

Explanation:

Step1: Identify mole ratio

From the reaction \( 2\text{Al}(s) + 3\text{FeO}(s)
ightarrow 3\text{Fe}(s) + \text{Al}_2\text{O}_3(s) \), the mole ratio of \(\text{Al}\) to \(\text{FeO}\) is \( \frac{2}{3} \).

Step2: Calculate moles of Al

Let \( n_{\text{Al}} \) be moles of Al. Using the ratio: \( n_{\text{Al}} = 1.2\ \text{mol FeO} \times \frac{2\ \text{mol Al}}{3\ \text{mol FeO}} \)
\( n_{\text{Al}} = \frac{1.2 \times 2}{3} = 0.8\ \text{mol} \)

Answer:

0.8 mol