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a = a_0(\\frac{1}{2})^n 5) (3) how many pennium half - lives would 71.5…

Question

a = a_0(\frac{1}{2})^n

  1. (3) how many pennium half - lives would 71.5 seconds be?

Explanation:

Step1: Identify the concept

The problem is about calculating the number of half - lives.

Step2: Use the formula

If we assume the time for one half - life is \(t_{1/2}\), and the total time is \(T\), the number of half - lives \(n=\frac{T}{t_{1/2}}\). But here we are not given the time of one half - life of Pennium, assume the time of one half - life of Pennium is \(t_{1/2} = 1\) second for the sake of finding the number of half - lives in a given time. Then \(n=\frac{71.5}{1}=71.5\).

Answer:

71.5