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Question
how many sides does a regular polygon have if each interior angle measures $140^\circ$?
Step1: Relate interior to exterior angle
The sum of an interior angle and its corresponding exterior angle of a polygon is $180^\circ$.
$\text{Exterior angle} = 180^\circ - 140^\circ = 40^\circ$
Step2: Use total exterior angle sum
The sum of all exterior angles of any regular polygon is $360^\circ$. Let $n$ be the number of sides.
$n = \frac{360^\circ}{\text{Measure of one exterior angle}}$
Step3: Calculate number of sides
Substitute the exterior angle value into the formula.
$n = \frac{360}{40} = 9$
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