Question

1. how much work is done in each one of these scenarios? (remember to use si units when using physics formulas)

scenarios	pushing a crate	pushing a car	lifting a 2×25kg masses
force	70n	300 n	490n
displacement	2m	40m	35cm
work ( w = f cdot s )	( w = f cdot s = )	( w = )	( w = )

Explanation:

Step1: Convert units to SI (crate)

Displacement $s=2\ \text{m}$ (already SI)

Step2: Calculate work for crate

$W = F \cdot s = 70\ \text{N} \times 2\ \text{m}$

Step3: Calculate work for car

$W = F \cdot s = 300\ \text{N} \times 40\ \text{m}$

Step4: Convert mass lift displacement

$35\ \text{cm} = 0.35\ \text{m}$

Step5: Calculate work for mass lift

$W = F \cdot s = 490\ \text{N} \times 0.35\ \text{m}$

Answer:

1. Pushing a crate: $140\ \text{J}$
2. Pushing a car: $12000\ \text{J}$
3. Lifting masses: $171.5\ \text{J}$