Question

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Explanation:

Step1: Analyze $\text{PF}_3$

Central P has 3 bonding pairs + 1 lone pair. Electron domain geometry is tetrahedral, molecular geometry is trigonal pyramidal.

Step2: Analyze $\text{BeF}_2$

Central Be has 2 bonding pairs + 0 lone pairs. Molecular geometry is linear.

Step3: Analyze $\text{CCl}_4$

Central C has 4 bonding pairs + 0 lone pairs. Molecular geometry is tetrahedral.

Step4: Analyze $\text{GeF}_2$

Central Ge has 2 bonding pairs + 1 lone pair. Molecular geometry is bent.

Step5: Analyze $\text{BF}_3$

Central B has 3 bonding pairs + 0 lone pairs. Molecular geometry is trigonal planar.

Answer:

1. $\text{PF}_3$ → trigonal pyramidal
2. $\text{BeF}_2$ → linear
3. $\text{CCl}_4$ → tetrahedral
4. $\text{GeF}_2$ → bent
5. $\text{BF}_3$ → trigonal planar