Question

the hypotenuse of a 45°-45°-90° triangle measures 22√2 units. what is the length of one leg of the triangle? 11 units 11√2 units 22 units 22√2 units

Explanation:

Step1: Recall 45-45-90 triangle ratio

In a 45°-45°-90° triangle, hypotenuse $= \text{leg} \times \sqrt{2}$. Let leg length be $x$.

Step2: Set up equation

$$22\sqrt{2} = x \times \sqrt{2}$$

Step3: Solve for $x$

Divide both sides by $\sqrt{2}$:
$$x = \frac{22\sqrt{2}}{\sqrt{2}} = 22$$

Answer:

22 units (Option C)