QUESTION IMAGE
Question
the hypotenuse of a 45°-45°-90° triangle measures $22\sqrt{2}$ units.
what is the length of one leg of the triangle?
○ 11 units
○ $11\sqrt{2}$ units
○ 22 units
○ $22\sqrt{2}$ units
Step1: Recall 45-45-90 triangle ratio
For a 45°-45°-90° triangle, hypotenuse $= \text{leg} \times \sqrt{2}$, so $\text{leg} = \frac{\text{hypotenuse}}{\sqrt{2}}$.
Step2: Substitute hypotenuse value
Substitute hypotenuse $= 22\sqrt{2}$:
$\text{leg} = \frac{22\sqrt{2}}{\sqrt{2}}$
Step3: Simplify the expression
The $\sqrt{2}$ terms cancel out:
$\text{leg} = 22$
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22 units (Option C)