Question

the illustration provided shows two boys pulling on opposite ends of a rope with different amounts of force. left right 40 newtons 50 newtons what is the net force on the rope? 10n left 10n right 90n left 90n right

Explanation:

Step1: Define directions

Let the right - hand direction be positive and the left - hand direction be negative.

Step2: Identify forces

The force on the left is $F_{left}=- 40N$ and the force on the right is $F_{right}=50N$.

Step3: Calculate net force

The net force $F_{net}=F_{right}+F_{left}=50N+( - 40N)=10N$. Since the result is positive, the net force is in the right - hand direction.

Answer:

10N right