QUESTION IMAGE
Question
- images observed under the light microscope are reversed and inverted. suppose you were observing an organism through the microscope and noticed that it moved toward the bottom of the slide and then it moved to the right. what does this tell you about the actual movement of the organism?
the specimen is actually moving towards the ________ and ________ side of the slide.
( top / bottom ) ( right / left )
- describe the changes in the field of view and the amount of available light when going from low to high power using the compound microscope.
when going from low to high power on a compound microscope, the field of view gets __________
and the amount of light __________.
( larger / smaller ) ( increases / decreases )
- a microscope has a 20 x ocular (eyepiece) and two objectives of 10 x and 43 x respectively:
calculate the lowest total magnification of this microscope. show your work.
____ x __ = ____ lowest total magnification
Question 3
In a light microscope, images are reversed and inverted. So if the observed movement is down (bottom) and right, the actual movement is the opposite. Down in the view means up in actual, right in view means left in actual.
When switching from low to high power on a compound microscope, the field of view (the area seen) becomes smaller because the magnification increases, focusing on a smaller area. The amount of light decreases because the objective lens opening (numerical aperture) is smaller for higher power, letting in less light.
Step1: Recall total magnification formula
Total magnification ($M_{total}$) is the product of the ocular lens magnification ($M_{ocular}$) and the objective lens magnification ($M_{objective}$), i.e., $M_{total}=M_{ocular}\times M_{objective}$.
Step2: Identify lowest objective magnification
The ocular is 20X, and the objectives are 10X and 43X. The lowest objective magnification is 10X.
Step3: Calculate total magnification
Substitute into the formula: $M_{total}=20\times10 = 200$.
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