Question

the inequality $-x^2 - 6 < 0$ has0 critical pointscompletewhat is the solution set of $-x^2 - 6 < 0$?$o$${x | x in mathbb{r}}$done

Explanation:

Step1: Rearrange the inequality

$-x^2 - 6 < 0 \implies -x^2 < 6$

Step2: Multiply by -1 (reverse inequality)

$x^2 > -6$

Step3: Analyze the squared term

For all real $x$, $x^2 \geq 0$, so $x^2 > -6$ is always true.

Answer:

$\{x | x \in \mathbb{R}\}$