Question

instructions: draw and label the following structures on the next page: reactants wood (glucose): draw the number of these molecules as determined by the coefficients in your balanced equation: i drew a \zoom - in\ bubble with the appropriate number of wood molecules in it. oxygen: draw the number of these molecules as determined by the coefficient in your balanced equation: o=o i drew a \zoom - in\ bubble with the appropriate number of oxygen molecules in it. on your glucose and oxygen drawings, mark some bonds with an \x\ to indicate bonds breaking. draw an arrow labeled \heat in\ pointing to these molecules. write: \activation energy needed to break bonds\ underneath \heat in.\ products carbon dioxide: draw the number of these molecules as determined by the coefficient in your balanced equation: o=c=o i drew a \zoom - in\ bubble with the appropriate number of carbon dioxide molecules in it. water: draw the number of these molecules as determined by the coefficient in your balanced equation: i drew a \zoom - in\ bubble with the appropriate number of water molecules in it. draw an arrow labeled \heat out\ coming from these molecules. complete your model lastly, add color appropriately to your image to accurately represent a wildfire.

Explanation:

To solve this, we first need the balanced equation for the combustion of glucose (wood). The balanced equation for the combustion of glucose (\(C_6H_{12}O_6\)) is:

$$C_6H_{12}O_6 + 6O_2 ightarrow 6CO_2 + 6H_2O$$

Step 1: Determine the number of glucose molecules

From the balanced equation, the coefficient of glucose (\(C_6H_{12}O_6\)) is 1. So we draw 1 glucose molecule (the given structure represents glucose, \(C_6H_{12}O_6\)).

Step 2: Determine the number of oxygen molecules

The coefficient of \(O_2\) in the balanced equation is 6. So we draw 6 \(O_2\) molecules (each \(O_2\) is \(O=O\)).

Step 3: Determine the number of carbon dioxide molecules

The coefficient of \(CO_2\) is 6. So we draw 6 \(CO_2\) molecules (each \(CO_2\) is \(O=C=O\)).

Step 4: Determine the number of water molecules

The coefficient of \(H_2O\) is 6. So we draw 6 water molecules (each water is \(H-O-H\)).

Step 5: Mark bonds breaking and heat

• For glucose and oxygen, mark some bonds with "X" to show breaking (activation energy from "HEAT IN").
• For products, draw "HEAT OUT" arrow as energy is released in combustion.
• Add color (e.g., orange/red for fire, brown for wood, blue for water, etc.) to represent a wildfire.

Answer:

• Glucose: Draw 1 molecule (using the given structure).
• Oxygen: Draw 6 \(O=O\) molecules.
• Carbon Dioxide: Draw 6 \(O=C=O\) molecules.
• Water: Draw 6 \(H-O-H\) molecules.
• Mark bonds in reactants with "X", add "HEAT IN" (with activation energy note) and "HEAT OUT", then color appropriately for a wildfire.