Question

1. investigate: next to the graph, click the - button once to zoom out. the x - and y - axes should each range from about 0 to 70. click inside the graph until you have found three or four stable isotopes that have at least 50 protons. save these points.

a. which stable isotopes did you find?
b. do these have approximately equal numbers of neutrons and protons?
c. turn on show neutron:proton ratio. adjust the line until it lines up with the stable isotopes. approximately what n:p ratio do these isotopes have?

Explanation:

Step1: Identify stable isotopes

This requires knowledge of nuclear - physics and isotope stability. Commonly known stable isotopes with at least 50 protons include tin - 120 ($^{120}_{50}Sn$), tellurium - 128 ($^{128}_{52}Te$), xenon - 132 ($^{132}_{54}Xe$).

Step2: Analyze neutron - proton equality

For tin - 120: Protons ($p$) = 50, neutrons ($n$)=120 - 50 = 70. For tellurium - 128: $p = 52$, $n=128 - 52 = 76$. For xenon - 132: $p = 54$, $n=132 - 54 = 78$. They do not have approximately equal numbers of neutrons and protons.

Step3: Calculate neutron - proton ratio

For tin - 120: $\frac{n}{p}=\frac{70}{50}=1.4$. For tellurium - 128: $\frac{n}{p}=\frac{76}{52}\approx1.46$. For xenon - 132: $\frac{n}{p}=\frac{78}{54}\approx1.44$. The approximate n:p ratio is around 1.4 - 1.5.

Answer:

A. Tin - 120 ($^{120}_{50}Sn$), tellurium - 128 ($^{128}_{52}Te$), xenon - 132 ($^{132}_{54}Xe$)
B. No
C. Approximately 1.4 - 1.5