Question

1. ions -2

nitrogen
lose 2 electrons
nitrogen

protons: ______

neutrons: ______

electrons: ______

ion: ______

protons: ______

neutrons: ______

electrons: ______

ion: ______

Explanation:

Step1: Identify nitrogen's proton count

The atomic number of nitrogen is 7, so protons = 7. Protons do not change when forming ions.

Step2: Determine neutron count

For a neutral nitrogen atom (most common isotope, nitrogen-14), mass number = 14. Neutrons = mass number - protons = $14 - 7 = 7$. Neutrons do not change when losing electrons.

Step3: Count electrons in neutral N

A neutral atom has equal protons and electrons, so electrons = 7.

Step4: Calculate electrons in ion

Neutral N loses 2 electrons: $7 - 2 = 5$ electrons.

Step5: Determine ion charge

Charge = protons - electrons. For neutral N: $7 - 7 = 0$. For ion: $7 - 5 = +2$.

Answer:

Left (Neutral Nitrogen):

Protons: 7

Neutrons: 7

Electrons: 7

Ion: Neutral (no charge, N)

Right (Nitrogen Ion):

Protons: 7

Neutrons: 7

Electrons: 5

Ion: Nitrogen cation ($N^{2+}$)