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Question
in isosceles △tuv, • ∠u and ∠v are the base angles, and • m∠u is 56.5°. what is m∠t? a. 56.5° b. 67° c. 123.5° d. 113°
Step1: Recall base - angle property
In an isosceles triangle, base angles are equal. So $m\angle U=m\angle V = 56.5^{\circ}$.
Step2: Use angle - sum property of a triangle
The sum of the interior angles of a triangle is $180^{\circ}$. Let $m\angle T=x$. Then $x + m\angle U+m\angle V=180^{\circ}$. Substitute $m\angle U = 56.5^{\circ}$ and $m\angle V = 56.5^{\circ}$ into the equation: $x+56.5^{\circ}+56.5^{\circ}=180^{\circ}$.
Step3: Solve for $m\angle T$
$x=180^{\circ}-(56.5^{\circ}+56.5^{\circ})=180^{\circ}-113^{\circ}=67^{\circ}$.
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B. $67^{\circ}$