Question

item 20 (4 points) what is incorrect about these ipv6 addresses? ip address = error 3f10:4035::139c:192 contains two 4901:123c::f05f::42 contains two 2600:443fa::19cb:31 contains 5 dig choose 2600:ca54:d13a:2b01 contains a \g\; hex is only a - f contains two sets of double colons only 6 hextets contains 5 digits and characters; there are only 4 in each hextet

Explanation:

Step1: Recall IPv6 rules

In IPv6, a double - colon (::) can only be used once to represent consecutive groups of zeros for address compression. Each HEXTET (group separated by a colon) should have 4 hexadecimal digits or characters (0 - 9, A - F).

Step2: Analyze 3F10:4035::139C:192

There are two sets of double - colons, violating the single - use rule for double - colon compression.

Step3: Analyze 4901:123C::F05F::42

There are two sets of double - colons, violating the single - use rule for double - colon compression.

Step4: Analyze 2600:443FA::19CB:31

The group "443FA" has 5 characters. Each HEXTET should have 4, so this is incorrect.

Step5: Analyze 2600:ca54:d13a:2b01

All groups have 4 hexadecimal characters and there is no improper use of double - colon, so it is a valid IPv6 address representation.

Answer:

1. For 3F10:4035::139C:192: Contains two sets of double - colons
2. For 4901:123C::F05F::42: Contains two sets of double - colons
3. For 2600:443FA::19CB:31: Contains 5 digits and characters; there are only 4 in each HEXTET
4. For 2600:ca54:d13a:2b01: No error