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5. a jar contains 2 caramels, 7 mints and 16 dark chocolates. what is t…

Question

  1. a jar contains 2 caramels, 7 mints and 16 dark chocolates. what is the probability of choosing a dark chocolate, eating it, then choosing a caramel? simplified fraction: \square percent: \square %

Explanation:

Step1: Calculate total candies

Total = $2 + 7 + 16 = 25$

Step2: Probability of dark chocolate

$P(\text{dark}) = \frac{16}{25}$

Step3: Probability of caramel (after dark)

Now total = $25 - 1 = 24$, so $P(\text{caramel}) = \frac{2}{24} = \frac{1}{12}$

Step4: Multiply the two probabilities

$P(\text{both}) = \frac{16}{25} \times \frac{1}{12} = \frac{16}{300} = \frac{4}{75}$

Step5: Convert to percentage

$\frac{4}{75} \times 100 = \frac{400}{75} \approx 5.33$

Answer:

Simplified Fraction: $\frac{4}{75}$
Percent: $5.33$%