Question

jayla and her friends are playing a card game that includes spinning two spinners on each turn.

• spinner a has four equal sections labeled draw, play, take, and give that determine what the player will do with the cards.
• spinner b has three equal sections numbered 1, 2, and 3 that determine the number of cards the player will use.

what is the probability that a player spins give and 3 on their turn?

Explanation:

Step1: Calculate probability of spinning 'give' on Spinner A

Spinner A has 4 equal - sections. The probability of spinning 'give' on Spinner A, denoted as $P(A)$, is $\frac{1}{4}$ since there is 1 'give' section out of 4.

Step2: Calculate probability of spinning 3 on Spinner B

Spinner B has 3 equal - sections. The probability of spinning 3 on Spinner B, denoted as $P(B)$, is $\frac{1}{3}$ since there is 1 section numbered 3 out of 3.

Step3: Use the multiplication rule for independent events

Since the spins of the two spinners are independent events, the probability of both events occurring is the product of their individual probabilities. So $P = P(A)\times P(B)$.
$P=\frac{1}{4}\times\frac{1}{3}=\frac{1}{12}$

Answer:

$\frac{1}{12}$