Question

∠jkl is a right angle. what are m∠jkm and m∠mkl? (12x + 3)° (6x - 3)° solve. 63, 27 63, 33 5, 33 30, 60

Explanation:

Step1: Use angle - sum property

Since $\angle{JKL}$ is a right - angle ($90^{\circ}$) and $\angle{JKM}=(12x + 3)^{\circ}$ and $\angle{MKL}=(6x-3)^{\circ}$, we know that $\angle{JKM}+\angle{MKL}=\angle{JKL}$. So, $(12x + 3)+(6x - 3)=90$.

Step2: Simplify the left - hand side of the equation

Combine like terms: $12x+6x+3 - 3=90$, which simplifies to $18x=90$.

Step3: Solve for x

Divide both sides of the equation $18x = 90$ by 18: $x=\frac{90}{18}=5$.

Step4: Find $\angle{JKM}$ and $\angle{MKL}$

For $\angle{JKM}$, substitute $x = 5$ into the expression $12x+3$: $\angle{JKM}=12\times5+3=60 + 3=63^{\circ}$.
For $\angle{MKL}$, substitute $x = 5$ into the expression $6x - 3$: $\angle{MKL}=6\times5-3=30 - 3=27^{\circ}$.

Answer:

$63,27$