Question

jump to level 1
complete the code to output g =followed by the value of g to three digits after the decimal point. on the same line, output when m =followed by the value of m to two digits after the decimal point. end with a newline.
ex: if the input is 2.20, then the output is:
g = 30.400 when m = 2.20
note: setprecision(x) can be used in an output statement to print a double to x digits after the decimal point.
1 #include <iomanip>
2 #include <iostream>
3 using namespace std;
4
5 int main() {
6 double m;
7 double g;
8
9 cin >> m;
10
11 g=(7.0 m m)-(4.5 * m)+6.5;
12
13 cout << \g =\<< fixed << setprecision(3)<< g << \, m =\<< fixed << setprecision(2) << m << endl;
14
15
16 return 0;
17 }

Explanation:

Step1: Include necessary headers

The code includes <iomanip> for setprecision and <iostream> for input - output operations.

#include <iomanip>
#include <iostream>
using namespace std;

Step2: Define variables

Two double variables m and g are defined to store the input value and the calculated value of g respectively.

int main() {
    double m;
    double g;

Step3: Take input

The program takes the value of m as input from the user.

    cin >> m;

Step4: Calculate g

The formula g=(7.0 m m)-(4.5 * m)+6.5 is used to calculate the value of g.

    g=(7.0 * m * m)-(4.5 * m)+6.5;

Step5: Output results

The program outputs the value of g with three decimal places and the value of m with two decimal places on the same line, followed by a newline.

    cout << "g = " << fixed << setprecision(3) << g << "; m =" << fixed << setprecision(2) << m << endl;
    return 0;
}

Answer:

The complete code is:

#include <iomanip>
#include <iostream>
using namespace std;
int main() {
    double m;
    double g;
    cin >> m;
    g=(7.0 * m * m)-(4.5 * m)+6.5;
    cout << "g = " << fixed << setprecision(3) << g << "; m =" << fixed << setprecision(2) << m << endl;
    return 0;
}