Question

a 1 kg object changes its velocity from 2 m/s to 5 m/s. what is the change in momentum? $j = m (v_f - v_i)$
options: $7\text{kg} \cdot \text{m/s}$, $5\text{kg} \cdot \text{m/s}$, $2\text{kg} \cdot \text{m/s}$, $3\text{kg} \cdot \text{m/s}$

Explanation:

Step1: Identify given values

$m = 1\ \text{kg}$, $v_i = 2\ \text{m/s}$, $v_f = 5\ \text{m/s}$

Step2: Apply change in momentum formula

$\Delta p = m(v_f - v_i)$

Step3: Substitute values and calculate

$\Delta p = 1\ \text{kg} \times (5\ \text{m/s} - 2\ \text{m/s}) = 1 \times 3 = 3\ \text{kg·m/s}$

Answer:

3 kg·m/s