Question

a 5 kg object is pulled by a 50 n applied force. the object experiences 20 n of friction. what is the resulting acceleration? 10 m/s^2 6 m/s^2 14 m/s^2 4 m/s^2

Explanation:

Step1: Calculate net - force

The net - force $F_{net}$ is the applied force minus the frictional force. Given $F_{applied}=50N$ and $F_{friction}=20N$, so $F_{net}=F_{applied}-F_{friction}=50 - 20=30N$.

Step2: Use Newton's second law

Newton's second law is $F = ma$, where $F$ is the net - force, $m$ is the mass, and $a$ is the acceleration. We know $F_{net}=30N$ and $m = 5kg$. Rearranging the formula for acceleration gives $a=\frac{F_{net}}{m}$. Substituting the values, we have $a=\frac{30}{5}=6m/s^{2}$.

Answer:

$6m/s^{2}$