Question

lab questions

1. record your results. (c - 10 marks)

metals	kcl	fe(no₃)₂	cacl₂	na₂co₃	hcl
zn
mg

1. for each single displacement reaction write a balance chemical equation. if there is no reaction, write nr> (k/u - 10 marks)

cu + kcl → nr
cu + fe(no₃)₂ → nr
cu + cacl₂ → nr
cu + na₂co₃ → nr
cu + hcl → nr
zn + kcl → nr
zn + fe(no₃)₂ → zn(no₃)₂+fe
zn + cacl₂ → nr
zn + na₂co₃ → nr

Explanation:

Step1: Recall metal - activity series

Use the metal - activity series to determine if single - displacement reactions occur. A more reactive metal can displace a less reactive metal from its compound.

Step2: Analyze reactions for Cu

Copper (Cu) is less reactive than potassium (K), iron (Fe), calcium (Ca), and sodium (Na). So, Cu + KCl → NR, Cu+Fe(NO₃)₂ → NR, Cu + CaCl₂ → NR, Cu+Na₂CO₃ → NR, Cu + HCl → NR because Cu cannot displace these metals from their compounds.

Step3: Analyze reactions for Zn

Zinc (Zn) is less reactive than potassium (K) and calcium (Ca), so Zn + KCl → NR, Zn + CaCl₂ → NR. Zinc is more reactive than iron (Fe), so the reaction Zn + Fe(NO₃)₂→Zn(NO₃)₂ + Fe occurs. Zinc is less reactive than sodium (Na), so Zn+Na₂CO₃ → NR.

Step4: Analyze reactions for Mg

Since no reactions with Mg are partially shown in the given work, we assume we follow the same principle. Magnesium is a very reactive metal. For example, Mg + 2HCl→MgCl₂ + H₂ (if we consider reaction with HCl). But based on the given incomplete work, we focus on the reactions shown for Cu and Zn.

The balanced chemical equation for the reaction that occurs (Zn + Fe(NO₃)₂→Zn(NO₃)₂ + Fe) is already in balanced form as there is 1 Zn, 1 Fe, 2 N, and 6 O on both sides of the equation.

Answer:

Cu + KCl → NR
Cu + Fe(NO₃)₂ → NR
Cu + CaCl₂ → NR
Cu + Na₂CO₃ → NR
Cu + HCl → NR
Zn + KCl → NR
Zn + Fe(NO₃)₂→Zn(NO₃)₂ + Fe
Zn + CaCl₂ → NR
Zn + Na₂CO₃ → NR