Question

(d) le quadruple d’un nombre diminué de 2 est égal à 48 augmenté de deux fois ce nombre. trouve ce nombre.

Explanation:

Let the number be \( x \).

Step 1: Translate the problem into an equation

The quadruple of the number diminished by 2 is \( 4x - 2 \).
48 augmented by two times the number is \( 48 + 2x \).
Since they are equal, we have the equation: \( 4x - 2 = 48 + 2x \)

Step 2: Solve for \( x \)

Subtract \( 2x \) from both sides: \( 4x - 2x - 2 = 48 + 2x - 2x \)
Simplify: \( 2x - 2 = 48 \)
Add 2 to both sides: \( 2x - 2 + 2 = 48 + 2 \)
Simplify: \( 2x = 50 \)
Divide both sides by 2: \( \frac{2x}{2} = \frac{50}{2} \)
Simplify: \( x = 25 \)

Answer:

The number is 25.