QUESTION IMAGE
Question
lesson 11.1 checkpoint
once you have completed the above problems and checked your solutions, complete the lesson checkpoint below.
complete the lesson reflection above by circling your current understanding of the learning goal.
- which of the following statements are true? select three that apply.
a. $x^{\frac{4}{5}}=sqrt5{x^{4}}$
b. $x^{\frac{2}{8}}=sqrt4{x}$
c. $(x^{\frac{1}{3}})^2 = (sqrt3{x})^2$
d. $(sqrt5{x^{4}})^2=x^{\frac{2}{5}}$
write the equivalent expression for the following expression with rational exponents.
- $x^{\frac{2}{7}}$
write the equivalent expression for the following radical expressions.
- $sqrt{x^{6}}$
Step1: Recall radical - exponent rule
The rule is $x^{\frac{m}{n}}=\sqrt[n]{x^{m}}$.
Step2: Analyze option A
For $x^{\frac{4}{5}}$, by the rule $x^{\frac{m}{n}}=\sqrt[n]{x^{m}}$, when $m = 4$ and $n = 5$, we have $x^{\frac{4}{5}}=\sqrt[5]{x^{4}}$, so option A is true.
Step3: Analyze option B
For $x^{\frac{1}{8}}$, by the rule $x^{\frac{m}{n}}=\sqrt[n]{x^{m}}$, it should be $x^{\frac{1}{8}}=\sqrt[8]{x}$, not $\sqrt[4]{x}$, so option B is false.
Step4: Analyze option C
For $(x^{\frac{1}{3}})^2$, first $x^{\frac{1}{3}}=\sqrt[3]{x}$, then $(x^{\frac{1}{3}})^2 = (\sqrt[3]{x})^2$, so option C is true.
Step5: Analyze option D
For $(\sqrt[5]{x^{4}})^2$, since $\sqrt[5]{x^{4}}=x^{\frac{4}{5}}$, then $(\sqrt[5]{x^{4}})^2=(x^{\frac{4}{5}})^2=x^{\frac{8}{5}}$, not $x^{\frac{2}{5}}$, so option D is false.
Step6: Rewrite $x^{\frac{2}{7}}$ as a radical
By the rule $x^{\frac{m}{n}}=\sqrt[n]{x^{m}}$, $x^{\frac{2}{7}}=\sqrt[7]{x^{2}}$.
Step7: Rewrite $\sqrt{x^{6}}$ with a rational - exponent
Since $\sqrt{x^{6}}=(x^{6})^{\frac{1}{2}}$, and using the power - of - a - power rule $(a^{m})^{n}=a^{mn}$, we have $(x^{6})^{\frac{1}{2}}=x^{3}$.
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- A. $x^{\frac{4}{5}}=\sqrt[5]{x^{4}}$, C. $(x^{\frac{1}{3}})^2 = (\sqrt[3]{x})^2$
- $\sqrt[7]{x^{2}}$
- $x^{3}$