Question

the line of best fit to model the data in the table is y = 5.2x - 0.4. what is the residual for 5? -1.6 -0.6 0.6 1.6 x y 1 8 2 13 3 18 4 23 5 24

Explanation:

Step1: Find predicted value

Substitute $x = 5$ into $y=5.2x - 0.4$. So $y_{predicted}=5.2\times5 - 0.4=26 - 0.4 = 25.6$.

Step2: Calculate residual

Residual is $y_{actual}-y_{predicted}$. Given $y_{actual}=24$ when $x = 5$. So residual $=24 - 25.6=-1.6$.

Answer:

-1.6